Optimal. Leaf size=234 \[ -\frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{2 x^2}-\frac {f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {f^2 m \log (e+f x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {f m \left (a+b \log \left (c x^n\right )\right )}{2 e x}-\frac {b n \log \left (d (e+f x)^m\right )}{4 x^2}-\frac {b f^2 m n \text {Li}_2\left (\frac {f x}{e}+1\right )}{2 e^2}+\frac {b f^2 m n \log ^2(x)}{4 e^2}-\frac {b f^2 m n \log (x)}{4 e^2}+\frac {b f^2 m n \log (e+f x)}{4 e^2}-\frac {b f^2 m n \log \left (-\frac {f x}{e}\right ) \log (e+f x)}{2 e^2}-\frac {3 b f m n}{4 e x} \]
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Rubi [A] time = 0.16, antiderivative size = 234, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2395, 44, 2376, 2301, 2394, 2315} \[ -\frac {b f^2 m n \text {PolyLog}\left (2,\frac {f x}{e}+1\right )}{2 e^2}-\frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{2 x^2}-\frac {f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {f^2 m \log (e+f x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {f m \left (a+b \log \left (c x^n\right )\right )}{2 e x}-\frac {b n \log \left (d (e+f x)^m\right )}{4 x^2}+\frac {b f^2 m n \log ^2(x)}{4 e^2}-\frac {b f^2 m n \log (x)}{4 e^2}+\frac {b f^2 m n \log (e+f x)}{4 e^2}-\frac {b f^2 m n \log \left (-\frac {f x}{e}\right ) \log (e+f x)}{2 e^2}-\frac {3 b f m n}{4 e x} \]
Antiderivative was successfully verified.
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Rule 44
Rule 2301
Rule 2315
Rule 2376
Rule 2394
Rule 2395
Rubi steps
\begin {align*} \int \frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{x^3} \, dx &=-\frac {f m \left (a+b \log \left (c x^n\right )\right )}{2 e x}-\frac {f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {f^2 m \left (a+b \log \left (c x^n\right )\right ) \log (e+f x)}{2 e^2}-\frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{2 x^2}-(b n) \int \left (-\frac {f m}{2 e x^2}-\frac {f^2 m \log (x)}{2 e^2 x}+\frac {f^2 m \log (e+f x)}{2 e^2 x}-\frac {\log \left (d (e+f x)^m\right )}{2 x^3}\right ) \, dx\\ &=-\frac {b f m n}{2 e x}-\frac {f m \left (a+b \log \left (c x^n\right )\right )}{2 e x}-\frac {f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {f^2 m \left (a+b \log \left (c x^n\right )\right ) \log (e+f x)}{2 e^2}-\frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{2 x^2}+\frac {1}{2} (b n) \int \frac {\log \left (d (e+f x)^m\right )}{x^3} \, dx+\frac {\left (b f^2 m n\right ) \int \frac {\log (x)}{x} \, dx}{2 e^2}-\frac {\left (b f^2 m n\right ) \int \frac {\log (e+f x)}{x} \, dx}{2 e^2}\\ &=-\frac {b f m n}{2 e x}+\frac {b f^2 m n \log ^2(x)}{4 e^2}-\frac {f m \left (a+b \log \left (c x^n\right )\right )}{2 e x}-\frac {f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {b f^2 m n \log \left (-\frac {f x}{e}\right ) \log (e+f x)}{2 e^2}+\frac {f^2 m \left (a+b \log \left (c x^n\right )\right ) \log (e+f x)}{2 e^2}-\frac {b n \log \left (d (e+f x)^m\right )}{4 x^2}-\frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{2 x^2}+\frac {1}{4} (b f m n) \int \frac {1}{x^2 (e+f x)} \, dx+\frac {\left (b f^3 m n\right ) \int \frac {\log \left (-\frac {f x}{e}\right )}{e+f x} \, dx}{2 e^2}\\ &=-\frac {b f m n}{2 e x}+\frac {b f^2 m n \log ^2(x)}{4 e^2}-\frac {f m \left (a+b \log \left (c x^n\right )\right )}{2 e x}-\frac {f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {b f^2 m n \log \left (-\frac {f x}{e}\right ) \log (e+f x)}{2 e^2}+\frac {f^2 m \left (a+b \log \left (c x^n\right )\right ) \log (e+f x)}{2 e^2}-\frac {b n \log \left (d (e+f x)^m\right )}{4 x^2}-\frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{2 x^2}-\frac {b f^2 m n \text {Li}_2\left (1+\frac {f x}{e}\right )}{2 e^2}+\frac {1}{4} (b f m n) \int \left (\frac {1}{e x^2}-\frac {f}{e^2 x}+\frac {f^2}{e^2 (e+f x)}\right ) \, dx\\ &=-\frac {3 b f m n}{4 e x}-\frac {b f^2 m n \log (x)}{4 e^2}+\frac {b f^2 m n \log ^2(x)}{4 e^2}-\frac {f m \left (a+b \log \left (c x^n\right )\right )}{2 e x}-\frac {f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {b f^2 m n \log (e+f x)}{4 e^2}-\frac {b f^2 m n \log \left (-\frac {f x}{e}\right ) \log (e+f x)}{2 e^2}+\frac {f^2 m \left (a+b \log \left (c x^n\right )\right ) \log (e+f x)}{2 e^2}-\frac {b n \log \left (d (e+f x)^m\right )}{4 x^2}-\frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d (e+f x)^m\right )}{2 x^2}-\frac {b f^2 m n \text {Li}_2\left (1+\frac {f x}{e}\right )}{2 e^2}\\ \end {align*}
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Mathematica [A] time = 0.15, size = 232, normalized size = 0.99 \[ -\frac {f^2 m x^2 \log (x) \left (2 a+2 b \log \left (c x^n\right )+2 b n \log (e+f x)-2 b n \log \left (\frac {f x}{e}+1\right )+b n\right )+2 a e^2 \log \left (d (e+f x)^m\right )-2 a f^2 m x^2 \log (e+f x)+2 a e f m x+2 b e^2 \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )-2 b f^2 m x^2 \log \left (c x^n\right ) \log (e+f x)+2 b e f m x \log \left (c x^n\right )+b e^2 n \log \left (d (e+f x)^m\right )-2 b f^2 m n x^2 \text {Li}_2\left (-\frac {f x}{e}\right )-b f^2 m n x^2 \log (e+f x)+3 b e f m n x-b f^2 m n x^2 \log ^2(x)}{4 e^2 x^2} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.54, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (b \log \left (c x^{n}\right ) + a\right )} \log \left ({\left (f x + e\right )}^{m} d\right )}{x^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \log \left (c x^{n}\right ) + a\right )} \log \left ({\left (f x + e\right )}^{m} d\right )}{x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.69, size = 2100, normalized size = 8.97 \[ \text {Expression too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 2.37, size = 285, normalized size = 1.22 \[ \frac {{\left (\log \left (\frac {f x}{e} + 1\right ) \log \relax (x) + {\rm Li}_2\left (-\frac {f x}{e}\right )\right )} b f^{2} m n}{2 \, e^{2}} + \frac {{\left (2 \, a f^{2} m + {\left (f^{2} m n + 2 \, f^{2} m \log \relax (c)\right )} b\right )} \log \left (f x + e\right )}{4 \, e^{2}} - \frac {2 \, b f^{2} m n x^{2} \log \left (f x + e\right ) \log \relax (x) - b f^{2} m n x^{2} \log \relax (x)^{2} + 2 \, a e^{2} \log \relax (d) + {\left (2 \, a f^{2} m + {\left (f^{2} m n + 2 \, f^{2} m \log \relax (c)\right )} b\right )} x^{2} \log \relax (x) + {\left (e^{2} n \log \relax (d) + 2 \, e^{2} \log \relax (c) \log \relax (d)\right )} b + {\left (2 \, a e f m + {\left (3 \, e f m n + 2 \, e f m \log \relax (c)\right )} b\right )} x + {\left (2 \, b e^{2} \log \left (x^{n}\right ) + 2 \, a e^{2} + {\left (e^{2} n + 2 \, e^{2} \log \relax (c)\right )} b\right )} \log \left ({\left (f x + e\right )}^{m}\right ) - 2 \, {\left (b f^{2} m x^{2} \log \left (f x + e\right ) - b f^{2} m x^{2} \log \relax (x) - b e f m x - b e^{2} \log \relax (d)\right )} \log \left (x^{n}\right )}{4 \, e^{2} x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\ln \left (d\,{\left (e+f\,x\right )}^m\right )\,\left (a+b\,\ln \left (c\,x^n\right )\right )}{x^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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